What is the minimum number of 10-ohm, one-ampere resistors needed to achieve an equivalent resistance of 10 ohms capable of carrying a two-ampere load?

Prepare for the MTA Transit Electrical Helper Exam No. 4612. Study using flashcards and multiple choice questions, each with hints and explanations. Get ready for your test!

Multiple Choice

What is the minimum number of 10-ohm, one-ampere resistors needed to achieve an equivalent resistance of 10 ohms capable of carrying a two-ampere load?

Explanation:
To achieve an equivalent resistance of 10 ohms while also being able to carry a two-ampere load, it’s essential to consider how resistors can be arranged in series and parallel configurations. Each of the resistors has a resistance of 10 ohms and can carry a load of 1 amp. If these resistors are connected in parallel, the formula for calculating equivalent resistance is given by: \[ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots \] For resistors in parallel, the equivalent resistance decreases. If we want the total resistance to stay at 10 ohms with a two-ampere load, we must consider that we need to use enough resistors to handle that current safely without exceeding the limit of each individual resistor. Using four 10-ohm resistors in parallel can be calculated as follows: \[ R_{\text{eq}} = \frac{10\, \Omega}{n} \] where n is the number of resistors. Setting the equivalent resistance to 10 ohms: \[ 10\,

To achieve an equivalent resistance of 10 ohms while also being able to carry a two-ampere load, it’s essential to consider how resistors can be arranged in series and parallel configurations.

Each of the resistors has a resistance of 10 ohms and can carry a load of 1 amp. If these resistors are connected in parallel, the formula for calculating equivalent resistance is given by:

[

\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots

]

For resistors in parallel, the equivalent resistance decreases. If we want the total resistance to stay at 10 ohms with a two-ampere load, we must consider that we need to use enough resistors to handle that current safely without exceeding the limit of each individual resistor.

Using four 10-ohm resistors in parallel can be calculated as follows:

[

R_{\text{eq}} = \frac{10, \Omega}{n}

]

where n is the number of resistors. Setting the equivalent resistance to 10 ohms:

[

10,

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